Python 练习实例68
题目:有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数
程序分析:无。
程序源代码:
#!/usr/bin/python # -*- coding: UTF-8 -*- if __name__ == '__main__': n = int(raw_input('the total number is:\n')) m = int(raw_input('back m:\n')) def move(array,n,m): array_end = array[n - 1] for i in range(n - 1,-1,- 1): array[i] = array[i - 1] array[0] = array_end m -= 1 if m > 0:move(array,n,m) number = [] for i in range(n): number.append(int(raw_input('input a number:\n'))) print 'orignal number:',number move(number,n,m) print 'after moved:',number
以上实例输出结果为:
the total number is: 8 back m: 5 input a number: 2 input a number: 8 input a number: 6 input a number: 1 input a number: 78 input a number: 45 input a number: 34 input a number: 2 orignal number: [2, 8, 6, 1, 78, 45, 34, 2] after moved: [1, 78, 45, 34, 2, 2, 8, 6]